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Code Pull requests Releases 2 Packages Activity

feat: connect reblogs + direct reply in home timeline

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patak 2022-12-28 09:34:58 +01:00
parent 107ac8a6b9
commit 010bfc4179
2 changed files with 5 additions and 3 deletions
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5
components/status/StatusCard.vue
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@ -26,8 +26,9 @@ const status = $computed(() => {
}) })
// Use original status, avoid connecting a reblog (review if we should relax this) // Use original status, avoid connecting a reblog (review if we should relax this)
const directReply = $computed(() => props.hasNewer || (!!props.status.inReplyToId && props.status.inReplyToId === props.newer?.id)) const directReply = $computed(() => props.hasNewer || (!!props.status.inReplyToId && (props.status.inReplyToId === props.newer?.id || props.status.inReplyToId === props.newer?.reblog?.id)))
const connectReply = $computed(() => props.hasOlder || props.status.id === props.older?.inReplyToId) // Use reblogged status, connect it to further replies
const connectReply = $computed(() => props.hasOlder || status.id === props.older?.inReplyToId)
const rebloggedBy = $computed(() => props.status.reblog ? props.status.account : null) const rebloggedBy = $computed(() => props.status.reblog ? props.status.account : null)

3
components/timeline/TimelineHome.vue
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@ -10,7 +10,8 @@ function preprocess(items: Status[]) {
// TODO: Basic reordering, we should get something more efficient and robust // TODO: Basic reordering, we should get something more efficient and robust
for (let i = items.length - 1; i > 0; i--) { for (let i = items.length - 1; i > 0; i--) {
for (let k = 1; k <= maxDistance && i - k >= 0; k++) { for (let k = 1; k <= maxDistance && i - k >= 0; k++) {
if (newItems[i - k].inReplyToId === newItems[i].id) { const inReplyToId = newItems[i - k].inReplyToId // TODO: ?? newItems[i - k].reblog?.inReplyToId
if (inReplyToId === newItems[i].reblog?.id || inReplyToId === newItems[i].id) {
const item = newItems.splice(i, 1)[0] const item = newItems.splice(i, 1)[0]
newItems.splice(i - k, 0, item) newItems.splice(i - k, 0, item)
k = 1 k = 1